# Line slope calculator x+10y=40

**Straight line given by points A[0; 4] and B[10; 3]**

## Calculation:

**Slope-intercept form of line:**y = -0.1x+4

**Canonical form of the line equation:**x+10y-40 = 0

**Parametric form of the line equation:**

x = 10t

y = -t+4 ; t ∈ R

**Slope:**m = -0.1

**Slope angle of line: φ =**-5°42'38″ = -0.0997 rad

**X intercept:**x

_{0}= 40

**Y intercept:**y

_{0}= q = 4

**Distance line from the origin:**d

_{0}= 3.9801

**The length of the segment AB: |AB| =**10.0499

**Vector: AB =**(10; -1)

**Normal vector: n =**(1; 10)

**Midpoint of the segment AB: M =**[5; 3.5]

**Perpendicular Bisector equation:**10x-y-46.5 = 0

**Vector OA = (0; 4) ; |OA| = 4**

**Vector OB = (10; 3) ; |OB| = 10.4403**

**Scalar product OA .OB = 12**

**Angle ∠ AOB = 73°18'3″ = 1.2793 rad**